Wherever matrix holds a 0, the whole row and the whole column of that cell must be 0 in the result. Only the zeros that were in matrix at the start count. A zero created by this rule does not spread any further.
the single 0 in row 1, column 1 clears its own row and its own column.
Example 2
Input
matrix = [[3, 0, 5], [2, 6, 0], [7, 1, 4]]
Output
[[0, 0, 0], [0, 0, 0], [7, 0, 0]]
Explanation
the zeros sit in rows 0 and 1 and in columns 1 and 2, so only the 7 in the bottom-left corner survives. The new zero in the top-left corner does not clear column 0.
Constraints:
matrix has at least one row, and every row has the same length
Follow-up: can you do it inside matrix itself, with a constant amount of extra memory, and return it?
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